Regular expression problem

mukesh tiwari mukeshtiwari.iiitm at gmail.com
Sun Mar 10 18:42:29 CET 2013


Hello all 
I am trying to solve this problem[1] using regular expression. I wrote this code but I am getting time limit exceed. Could some one please tell me how to make this code run faster. 

import re

if __name__ == "__main__":
    n = int ( raw_input() )
    c = 1
    while c <= n :
        email =  filter ( lambda x : x !=  None , [ re.search ( '[^~!@#$%^&*()<>?,.]*[a-zA-Z0-9][a-zA-Z0-9._][a-zA-Z0-9._][a-zA-Z0-9._][a-zA-Z0-9._][a-zA-Z0-9._]*@[a-zA-Z0-9]+.(com|edu|org|co.in)[^~!@#$%^&*()<>?,.a-zA-Z0-9]*' , x ) for x in raw_input().split(' ') ] )
        t = len ( email )
        print 'Case #' + str ( c ) + ': ' + str ( t )
        for i in xrange ( t ):
            print email[i].group()
        c += 1

Also rather than breaking the string at space, I tried to use findall but I am not getting correct result. 

>>> re.findall ( '[^~!@#$%^&*()<>?,.]*[a-zA-Z0-9][a-zA-Z0-9._][a-zA-Z0-9._][a-zA-Z0-9._][a-zA-Z0-9._][a-zA-Z0-9._]*@[a-zA-Z0-9]+.(com|edu|org|co.in)[^~!@#$%^&*()<>?,.a-zA-Z0-9]*[ ]+','mukeshtiwari.iiitmmmm at gmail.com mukeshtiwari.iiitmmmmm at gmail.com')
['com']

I am suppose to get [ mukeshtiwari.iiitmmm at gmail.com , mukeshtiwari.iiitmmm at gmail.com] ?

Regards
Mukesh Tiwari

[1] http://www.spoj.com/problems/MAIN12C/



More information about the Python-list mailing list