Generating Filenames from Feeds
joel.goldstick at gmail.com
Thu Mar 14 17:05:05 CET 2013
On Thu, Mar 14, 2013 at 11:38 AM, Chuck <galois271 at gmail.com> wrote:
> HI all,
> I am trying to write a podcast catcher for fun, and I am trying to come up
> with a way to generate a destination filename to use in the function
> urlretrieve(url, destination). I would like the destination filename to
> end in a .mp3 extension.
> My first attempts were parsing out the <pubdate> and stripping the
> whitespace characters, and joining with os.path.join. I haven't been able
> to make that work for some reason.
The reason is apparently a syntax error.
Whenever I put the .mp3 in the os.path.join I get syntax errors. I am
> wondering if there is a better way?
Yes, don't write code with syntax errors!
> I was doing something like
> os.path.join('C:\\Users\\Me\\Music\\Podcasts\\', pubdate.mp3), where
> pubdate has been parsed and stripped of whitespace. I keep getting an
> error around the .mp3.
> Any ideas?
Seriously, if you don't post a minimal code example that shows the problem
and with a full traceback you are asking strangers to do magic tricks for
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