# Sudoku

Dave Angel davea at davea.name
Wed Mar 27 10:38:48 CET 2013

```On 03/27/2013 01:44 AM, Eric Parry wrote:

It'd be good to show where you found it, and credit the apparent author.
Bill Barksdale posted this in 2008 at:

http://stackoverflow.com/questions/201461/shortest-sudoku-solver-in-python-how-does-it-work

I don't know if there are older ones somewhere, but I didn't find any.
I did find places that quoted his code without attribution.

Another thing worth pointing out is that it's only valid for Python 2.x
(naturally, since I don't think Python 3 was out at that point)

using a link from Wikipedia and inserted the “most difficult Sudoku
puzzle ever” string into it and ran it. It worked fine and solved the
puzzle in about 4 seconds. However I cannot understand how it works. It
seems to go backwards and forwards at random. Can anyone explain how it
works in simple terms?
> Eric.
>
>
> def same_row(i,j): return (i/9 == j/9)
> def same_col(i,j): return (i-j) % 9 == 0
> def same_block(i,j): return (i/27 == j/27 and i%9/3 == j%9/3)
>
> def r(a):
>    i = a.find('0')
>    if i == -1:
>      print a
>      exit(a)
>
>    excluded_numbers = set()
>    for j in range(81):
>      if same_row(i,j) or same_col(i,j) or same_block(i,j):
>
>    for m in '123456789':
>      if m not in excluded_numbers:
>        # At this point, m is not excluded by any row, column, or block, so let's place it and recurse
>        r(a[:i]+m+a[i+1:])
>
> r('800000000003600000070090200050007000000045700000100030001000068008500010090000400')
> Sudoku solver where the puzzle is an 81 character string representing the puzzle read left-to-right, top-to-bottom, and 0 is a blank.
>
>

--
DaveA

```