Help printing the integers of a longer number
Chris Angelico
rosuav at gmail.com
Thu Mar 28 18:19:39 CET 2013
On Fri, Mar 29, 2013 at 4:11 AM, Jussi Piitulainen
<jpiitula at ling.helsinki.fi> wrote:
> Jussi Piitulainen writes:
>
>> khaosyt at gmail.com writes:
>>
>> > I want to print the individual numbers of a large number using
>> > division and modulus division.
>> >
>> > For example:
>> >
>> > Enter a positive integer: 54321
>> > 5
>> > 4
>> > 3
>> > 2
>> > 1
>>
>> Those numbers are called the digits of the large number.
>>
>> With divmod(54321, 10) you get both the number that is "left" after
>> removing the last digit, and the last digit:
>>
>> >>> left, last = divmod(54321, 10)
>> >>> left
>> 5432
>> >>> last
>> 1
>>
>> Define a function, print_digits(num), that prints the digits of the
>> non-negative integer num. Zero turns out fine so let's allow zero:
>>
>> def print_digits(num):
>> left, last = divmod(num, 10)
>> if left < 0: print the digits of left
>> print(last)
>
> Blush. That should be:
>
> ...
> if left > 0: ...
> ...
>
> (Or just "if left" because left will eventually be 0, positive numbers
> are true values, and 0 is a false value.)
>
> Sorry about that.
Sorry, I just nitpicked that very thing, hehe :)
Note that this doesn't work with negative numbers; it'll infinitely
recurse, due to divmod's behaviour. You'd need a special trap in there
to handle that:
if num<0:
print("-")
num=-num
# and continue.
ChrisA
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