Input wont work with if statement if it has a space
eli m
techgeek201 at gmail.com
Tue Mar 5 20:50:32 EST 2013
On Tuesday, March 5, 2013 3:47:31 PM UTC-8, emile wrote:
> On 03/05/2013 03:33 PM, eli m wrote:
>
> > On Tuesday, March 5, 2013 3:31:13 PM UTC-8, eli m wrote:
>
> >> Hi guys, i have a program like this: (A lot of code is not included)
>
> >>
>
> >> run = 0
>
> >>
>
> >> while run == 0:
>
> >>
>
> >> function = raw_input("Type in a function:")
>
> >>
>
> >> if function == "Example":
>
>
>
> whenever function isn't _exactly_ "Example" the else clause executes.
>
>
>
> If you want to catch forms of example you might try:
>
>
>
> if function.strip().upper() == "EXAMPLE":
>
>
>
> Emile
>
>
>
>
>
>
>
>
>
> >>
>
> >> print ("Hello World!")
>
> >>
>
> >> else:
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> >>
>
> >> print ("blah blah blah")
>
> >>
>
> >>
>
> >>
>
> >> The problem is that whenever i type in example with a space after it then it prints the else statement.
>
> >>
>
> >>
>
> >>
>
> >> My question is, how do i get it to except input with spaces?
>
> >
>
> > oops i meant function = raw_input("Type in a function:")
>
> >
Thank you!
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