Two Dictionaries and a Sum!
Roy Smith
roy at panix.com
Sat May 18 09:22:47 EDT 2013
In article <6012d69f-b65e-4d65-90c4-f04876853f5e at googlegroups.com>,
Bradley Wright <bradley.wright.biz at gmail.com> wrote:
> Confusing subject for a confusing problem (to a novice like me of course!)
> Thx for the help in advance folks
>
> I have (2) dictionaries:
>
> prices = {
> "banana": 4,
> "apple": 2,
> "orange": 1.5,
> "pear": 3
> }
>
> stock = {
> "banana": 6,
> "apple": 0,
> "orange": 32,
> "pear": 15
> }
>
> Here's my instructions:
Hmmm, homework for a class?
> consider this as an inventory and calculate the sum (thats 4*6 = 24 bananas!)
I suspect what you're trying to say is that bananas cost BTC 4 each, and
since you've got 6 bananas, you've got BTC 24 worth of bananas, yes?
And now you want to find the total value of your fruit supply?
>> HERES MY CODE:
>
> for key in prices:
> print prices[key]*stock[key]
>
> HERES THE OUTPUT:
>
> 48.0
> 45
> 24
> 0
So far, so good. A couple of things you may have noticed along the way:
1) Your orange unit price was a float, so the total value of all your
oranges is a float as well. That's how math works in Python.
2) The keys are presented in random order. To make the output easier to
interpret, you might want to do:
print key, prices[key]*stock[key]
> ISSUE:
> I need to find a way to add all of those together...any pointers?
The most straight-forward way would be something like:
total = 0
for key in prices:
fruit_subtotal = prices[key]*stock[key]
total += fruit_subtotal
print key, fruit_subtotal
print total
There are better ways to do this in Python, but start like this and get
that to work.
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