PEP 378: Format Specifier for Thousands Separator
Chris “Kwpolska” Warrick
kwpolska at gmail.com
Tue May 21 15:06:11 EDT 2013
On Tue, May 21, 2013 at 8:49 PM, Carlos Nepomuceno
<carlosnepomuceno at outlook.com> wrote:
> Thank you, but let me rephrase it. I'm already using str.format() but I'd like to use '%' (BINARY_MODULO) operator instead.
There is no real reason to do this. `str.format()` is the new shiny
thing you should be using all the time. Also, '%' is BINARY_MODULO
(where did you even get that name from?) if and only if you have two
numbers, and it performs the modulo division (eg. 27 % 5 = 2)
> So, the question is: Where would I change the CPython 2.7.5 source code to enable '%' (BINARY_MODULO) to format using the thousands separator like str.format() does, such as:
>
>>>>sys.stderr.write('%,d\n' % 1234567)
> 1,234,567
This will make your code unportable and useless, depending on one
patch you made. Please don’t do that. Instead,
> >>> sys.stdout.write('Number = %s\n' % '{:,.0f}'.format(x))
> Number = 12,345
>
> 'x' is unsigned integer so it's like using a sledgehammer to crack a nut!
In Python? Tough luck, every int is signed. And it isn’t just a
sledgehammer, it’s something worse. Just do that:
>>> sys.stdout.write('Number = {:,.0f}\n'.format(x))
Much more peaceful.
You can also do a print, like everyone sane would. Where did you
learn Python from? “Python Worst Practice for Dummies”?
--
Kwpolska <http://kwpolska.tk> | GPG KEY: 5EAAEA16
stop html mail | always bottom-post
http://asciiribbon.org | http://caliburn.nl/topposting.html
More information about the Python-list
mailing list