super in Python 3 and variadic arguments
Ian Kelly
ian.g.kelly at gmail.com
Thu Oct 10 22:33:37 EDT 2013
On Thu, Oct 10, 2013 at 8:11 PM, Steven D'Aprano
<steve+comp.lang.python at pearwood.info> wrote:
> One of the side-effects of this being a hack is that this doesn't work:
>
> class X(Y):
> def method(self, arg):
> f = super
> f().method(arg)
Actually, that works just fine. The compiler sees that super is
accessed within the method and creates the closure necessary to make
it work. This does fail, however:
f = super
class X(Y):
def method(self, arg):
f().method(arg)
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