Function for the path of the script?
Gary Herron
gary.herron at islandtraining.com
Sat Oct 26 22:52:31 EDT 2013
On 10/26/2013 07:23 PM, Peter Cacioppi wrote:
> Am I the only one who finds this function super useful?
>
> def _code_file() :
> return os.path.abspath(inspect.getsourcefile(_code_file))
>
>
> I've got one in every script. It's the only one I have to copy around. For my workflow ... so handy.
>
> I've got os.path.dirname aliased to dn, so its dn(_code_file()) that I find myself reaching for fairly often...
Huh? In what kind of a workflow are you running a python file without
knowing *what* file you are runnung?
Or am I just misinterpreting what this code does?
Confused but curious,
Gary Herron
More information about the Python-list
mailing list