object().__dict__
Pavel Volkov
sailor at lists.xtsubasa.org
Wed Apr 23 01:39:04 EDT 2014
There are some basics about Python objects I don't understand.
Consider this snippet:
>>> class X: pass
...
>>> x = X()
>>> dir(x)
['__class__', '__delattr__', '__dict__', '__dir__', '__doc__', '__eq__',
'__format__', '__ge__', '__getattribute__', '__gt__', '__hash__',
'__init__', '__le__', '__lt__', '__module__', '__ne__', '__new__',
'__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__',
'__str__', '__subclasshook__', '__weakref__']
>>> x.foo = 11
And now I want to make a simple object in a shorter way, without declaring
X class:
>>> y = object()
>>> dir(y)
['__class__', '__delattr__', '__dir__', '__doc__', '__eq__', '__format__',
'__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__',
'__lt__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__',
'__setattr__', '__sizeof__', '__str__', '__subclasshook__']
>>> y.foo = 12
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'object' object has no attribute 'foo'
The attribute list is different now and there's no __dict__ and the object
does not accept new attributes.
Please explain what's going on.
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