what is the "/" mean in __init__(self, /, *args, **kwargs) ?
Tim Chase
python.list at tim.thechases.com
Wed Aug 13 22:12:12 EDT 2014
On 2014-08-14 10:01, luofeiyu wrote:
> >>> help(int.__init__)
> Help on wrapper_descriptor:
>
> __init__(self, /, *args, **kwargs)
> Initialize self. See help(type(self)) for accurate signature.
>
> what is the "/" mean in __init__(self, /, *args, **kwargs) ?
Where are you seeing this?
Python 2.7.3 (default, Mar 13 2014, 11:03:55)
[GCC 4.7.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> help(int.__init__)
Help on wrapper_descriptor:
__init__(...)
x.__init__(...) initializes x; see help(type(x)) for signature
>>> ^D
Python 3.2.3 (default, Feb 20 2013, 14:44:27)
[GCC 4.7.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> help(int.__init__)
Help on wrapper_descriptor:
__init__(...)
x.__init__(...) initializes x; see help(type(x)) for signature
-tkc
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