why i can't get the sourcecode with inspect module?
Ben Finney
ben+python at benfinney.id.au
Tue Aug 19 23:21:48 EDT 2014
luofeiyu <elearn2014 at gmail.com> writes:
> >>> import inspect
> >>> def changer(x,y):
> ... return(x+y)
> ...
At this point, you have defined a function. It is accessible via the
‘changer’ name, and the code is available.
But the source code is not available; Python reads standard input but
doesn't preserve it.
> >>> dir()
> ['__builtins__', '__doc__', '__loader__', '__name__', '__package__', '__
> 'changer', 'inspect']
I don't know what this is meant to demonstrate.
Maybe ‘dir(changer.__code__)’ would be instructive.
> >>> inspect.getsource(changer)
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> File "D:\Python34\lib\inspect.py", line 830, in getsource
> lines, lnum = getsourcelines(object)
> File "D:\Python34\lib\inspect.py", line 819, in getsourcelines
> lines, lnum = findsource(object)
> File "D:\Python34\lib\inspect.py", line 667, in findsource
> raise OSError('could not get source code')
> OSError: could not get source code
> >>>
Exactly. The ‘inspect.getsource’ function gets the source code, if it's
available. The source code doesn't exist any more, so it's not
available; an OSError is raised.
--
\ “You say I took the name in vain / I don't even know the name / |
`\ But if I did, well, really, what's it to you?” —Leonard Cohen, |
_o__) _Hallelujah_ |
Ben Finney
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