when the method __get__ will be called?
luofeiyu
elearn2014 at gmail.com
Fri Aug 22 03:08:25 EDT 2014
class C(object):
a = 'abc'
def __getattribute__(self, *args, **kwargs):
print("__getattribute__() is called")
return object.__getattribute__(self, *args, **kwargs)
def __getattr__(self, name):
print("__getattr__() is called ")
return name + " from getattr"
def __get__(self, instance, owner):
print("__get__() is called", instance, owner)
return self
def foo(self, x):
print(x)
>>> x=C()
>>> x.a
__getattribute__() is called
'abc'
>>> x.b
__getattribute__() is called
__getattr__() is called
'b from getattr'
If call an attribute which does exist ,__getattribute__() is called
If call an attribute which does not exist ,__getattribute__() is called
and then __getattr__() is called ?
when the __get__ method will be called?no chance for my example?
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