intersection, union, difference, symmetric difference for dictionaries

mauro mauro at
Tue Feb 25 23:02:01 CET 2014

> {'A': 1} | {'A': 2}
> I would propose at least four:
>   {'A': 1}   # choose the LHS 
>   {'A': 2}   # choose the RHS 
>   {'A': (1,2)} # a resulting pair of both 
>   set(['A']) # you did set-ops, so you get a set

The implementation should define if LHS or RHS and user should change the 
order of operands depending on what he wants. 

Your example (as well as a many questions in shows 
that there is some need for these operations, that implemented in C in 
python library will be by far more CPU and memory efficient than 
implemented as you did. 

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