Printer list value problem

[Mike]

El martes, 14 de enero de 2014 16:32:49 UTC-3, MRAB  escribió:
> On 2014-01-14 19:24, Mike wrote:
> 
> > Hello,
> 
> > I confudsed,need printer the value of list (this is reaer from csv) . The reader is ok, but my problem is in the print moment because printer only the last value. For example my csv is:
> 
> >
> 
> > [........]
> 
> > user1 at example.com;user1;lastName;Name
> 
> > user2 at example.com;user2;lastName;Name
> 
> > [........]
> 
> >
> 
> > But when execute the script I view the print is only the last user
> 
> >
> 
> > [........]
> 
> > ca user2 at example.com displayName 'user2' sn 'lastName' cn 'Name'
> 
> > [........]
> 
> >
> 
> > And I need the next printer
> 
> >
> 
> > [........]
> 
> > ca user1 at example.com displayName 'User1' sn ''lastName" cn 'Name'
> 
> > ca user1 at example.com displayName 'User2' sn ''lastName" cn 'Name'
> 
> > [........]
> 
> >
> 
> > My script is
> 
> >
> 
> > [........]
> 
> > #!/usr/bin/python
> 
> > import csv
> 
> > with open ('users.csv', 'rb') as f:
> 
> >
> 
> >          reader = csv.reader (f, delimiter=';' ) #delimiter tabulador
> 
> >          for row in reader:
> 
> >
> 
> >                  mail     = row [0]
> 
> >                  name     = row [3]
> 
> >                  lastname = row [2]
> 
> >
> 
> 
> 
> This line is indented the same amount as the 'for' loop, which means
> 
> that it will be executed after the loop has finished.
> 
> 
> 
> >          print "ma {} displayName '{}' sn '{}'".format(mail,name,lastname)
> 
> >
> 
> You don't need to close the file here because the 'with' statement will
> 
> do that for you.
> 
> 
> 
> > f.close()
> 
> > [........]
> 
> >
> 
> >
> 
> > Thanks.
> 
> >

Hello MRAB,
I remove the "f.close" and after execute the script but still i have the same result (print the last row)

Thanks