Proper conversion of timestamp
Gregory Ewing
greg.ewing at canterbury.ac.nz
Tue Mar 4 23:06:47 EST 2014
Igor Korot wrote:
> What I have is a timestamp which reads: 1289410678L.
>
> Trying to convert this into the datetime object in Python using:
>
> import datetime
> datetime.datetime.fromtimestamp( stamp )
>
> produces the error: timestamp out of range for platform
> localtime()/gmtime() function.
Divide the timestamp by 1000.0 to give floating point
seconds, and then use datetime.fromtimestamp().
>>> d = datetime.datetime.fromtimestamp(1289410678 / 1000.0)
>>> d
datetime.datetime(1970, 1, 16, 10, 10, 10, 678000)
>>> d.strftime("%Y-%m-%d-%H:%M:%S.%f")[:-3]
'1970-01-16-10:10:10.678'
--
Greg
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