Dictionaries with variable default.

Antoon Pardon antoon.pardon at rece.vub.ac.be
Mon Nov 3 12:04:48 CET 2014


Is it possible to have a default dictionary where the default is dependant
on the key?

I was hoping something like this might work:
>>> m = defaultdict(lambda key: key+1)

But it obviously doesn't:
>>> m[3]

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: <lambda>() takes exactly 1 argument (0 given)

-- 
Antoon Pardon



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