"Natural" use of cmp= in sort
paddy3118 at gmail.com
Tue Nov 11 03:03:07 CET 2014
On Monday, 10 November 2014 19:44:39 UTC, Ian wrote:
> On Mon, Nov 10, 2014 at 12:19 PM, Peter Otten <xxx at yyy> wrote:
> > I'm not sure this works. I tried:
> Here's a simpler failure case.
> >>> ineq = """f2 > f3
> ... f3 > f1"""
> [Previously posted code elided]
> >>> greater_thans
> set([('f3', 'f1'), ('f2', 'f3')])
> >>> sorted(all_f, cmp=lambda t1, t2: 0 if t1==t2 else
> ... (1 if (t1, t2) not in greater_thans else -1))
> ['f1', 'f2', 'f3']
> Note that the greater_thans set is missing the implication by
> transitivity that f2 > f1, so the given cmp function would
> inconsistently return -1 for both comparisons cmp('f1', 'f2') and
> cmp('f2', 'f1').
Thanks. I will look into this...
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