python.list at tim.thechases.com
Wed Nov 26 13:56:06 CET 2014
On 2014-11-26 00:04, Tim Daneliuk wrote:
> someprog.py uname && sudo cat /etc/sudoers
> someprog.py uname && echo "sudo cat /etc/suoders"
> In the first instance, I need the sudo passoword, in the second I
This doesn't jibe with the pairs of quotes you sent and your request
for nesting. In most popular shells, the majority of your "quote"
characters don't actually quote anything:
bash$ echo // hello
bash$ echo /* hello */
[returns all the items in my root directory, the word "hello",
along with all the sub-directories in the current directory]
bash$ echo this#and#that
bash$ echo this # and #that
and has problems with things like
someprog.py uname && su""do cat /etc/sudoers
someprog.py uname && s"ud"o cat /etc/sudoers
which my shell will parse valid execution of sudo.
You state the problem as "I *just* want to find whether something is
quoted or not", but you have to clearly define what quoted means.
The standard library does provide the shlex module which comes fairly
close to what it sounds like you describe:
return "sudo" in shlex.split(corpus, comments="#")
but that still hiccups on
>>> is_sudo("echo I love sudo")
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