Where is path.py?
davea at davea.name
Thu Nov 27 16:34:51 CET 2014
On 11/27/2014 09:10 AM, David Aldrich wrote:
> I am running Python 2.7 on Windows 8.1. Today I installed path.py using easy_install:
> easy_install path.py
> The example code that I've seen imports path.py as follows:
> from path import path
> I am fairly new to Python and have a few questions about this:
> 1) Why is 'from path' required here?
The module called "path" evidently has a global symbol "path" in it.
That's unfortunate and very confusing, but it's pretty common. (See the
time function in the time module, standard library.) I don't know
anything about the module, but I'll make a wild guess that path is a
function. It doesn't matter, but it'll let me make explicit examples.
So the obvious approach to dealing with a module is to import it.
At that point, to call the above mentioned function, you would need to use:
result = path.path(arguments)
That gets confusing, so you might want a shortcut:
pathfunc = path.path
and now you can use
result = pathfunc(arguments)
The "from" logic facilitates that, by combining the import with the
assignment: The line:
from path import path
is equivalent to
import path; path = path.path
I don't know where path.py is, and it might be called something else,
such as path.pyc, or path.pyd, or ... But you can probably search for
it, if you like, with something like
dir /s c:\path.p*
I am assuming you're running on Windows, because you mention a Microsoft
IDE. If you were on Linux or Unix or Mac, you'd presumably use the find
> 2) I am using Microsoft's PTVS IDE to develop my code. It is not
displaying code completion for path.py (it works for the standard
libraries). How would I tell PTVS about path.py?
No clue about Microsoft's PTVS IDE; I hadn't heard of it before. But
if somebody else doesn't jump in, you should be able to use the Python
dir() and help() built-in functions. Then only work if the path
module is well written, of course.
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