generating unique variable name via loops
Peter Otten
__peter__ at web.de
Tue Nov 4 10:00:43 EST 2014
Fatih Güven wrote:
> 4 Kasım 2014 Salı 15:37:59 UTC+2 tarihinde Peter Otten yazdı:
>> Veek M wrote:
>>
>> > Fatih Güven wrote:
>> >
>> >> 4 Kas?m 2014 Sal? 13:29:34 UTC+2 tarihinde Fatih Güven yazd?:
>> >>> I want to generate a unique variable name for list using python.
>> >>>
>> >>> list1=...
>> >>> list2=...
>> >
>> > for x in range(1,10):
>> > exec("list%d = []" % x)
>>
>> Why would you do this?
>
> I have a structured and repetitive data.
I was actually asking "Veek M".
> I want to read a .txt file line
> by line and classified it to call easily. For example employee1 has a
> name, a salary, shift, age etc. and employee2 and other 101 employee have
> all of it.
>
> Call employee1.name or employee2.salary and assign it to a new variable,
> something etc.
I can only repeat my previous advice. Instead of creating variables for
employee1, employee2, and so on make a list of employees:
$ cat employees.txt
Peter,3000
Paul,2000
Mary,1000
$ cat employees.py
#!/usr/bin/env python3
import csv
class Employee:
def __init__(self, name, salary):
self.name = name
self.salary = salary
if __name__ == "__main__":
employees = []
with open("employees.txt") as f:
for row in csv.reader(f):
employees.append(Employee(row[0], int(row[1])))
for employee in employees:
print(employee.name, "-- salary:", employee.salary, "doubloons")
$ python3 employees.py
Peter -- salary: 3000 doubloons
Paul -- salary: 2000 doubloons
Mary -- salary: 1000 doubloons
You wouldn't want to reference Paul as employee2 -- what if the order in the
text file changed? Instead you can make a dict that maps name to employee...
employees_by_name = {}
for employee in employees:
name = employee.name
if name in employees_by_name:
raise ValueError("duplicate name {}".format(name))
employees_by_name[name] = employee
and use that dict to look up an employee:
while True:
name = input("enter a name ")
if name == "":
print("That's all folks")
break
if name not in employees_by_name:
print("unknown name")
else:
print("Salary:", employees_by_name[name].salary, "doubloons")
$ python3 employees.py
Peter -- salary: 3000 doubloons
Paul -- salary: 2000 doubloons
Mary -- salary: 1000 doubloons
enter a name Peter
Salary: 3000 doubloons
enter a name Mary
Salary: 1000 doubloons
enter a name paul
unknown name
enter a name Paul
Salary: 2000 doubloons
enter a name
That's all folks
$
More information about the Python-list
mailing list