Seymore4Head at Hotmail.invalid
Tue Oct 21 14:54:18 CEST 2014
On Tue, 21 Oct 2014 00:11:38 -0700, Larry Hudson <orgnut at yahoo.com>
>On 10/20/2014 12:49 PM, Seymore4Head wrote:
>> On Mon, 20 Oct 2014 20:40:18 +0100, MRAB <python at mrabarnett.plus.com>
>> Do you have to know the number of items the list will have before
>> making it?
>No, it is not necessary, lists are NOT the same as arrays in other languages. But it IS
>possible to create an initial list of a specific size:
>myList = [None] * 50
>That creates a 50-element list with each element set to None. (BTW, the indexes are from 0-49,
>not 0-50.) I have found this occasionally useful, but I'll emphasize, it's only RARELY useful.
> The .append() method is far more versatile.
>As to your original problem: my question to you is what is your purpose?
>1) To solve this particular problem, using Python.
>2) To explore the usage of lists, applying them to this problem.
>If your purpose is the first, then I agree with the advice you have already been given here.
>Dictionaries are a much better fit to this problem.
>If your purpose is the second, then go ahead and use this for your exploration. But realize
>that to more experienced Pythonistas this would be a very un-pythonic approach. Even better
>would be to try multiple approaches -- lists, dictionaries, lists with dictionaries,
>dictionaries with lists or tuples... And any other combinations you can come up with. This
>will give you even more experience, and allow you to evaluate the different approaches.
>And no, I will not give you a ready-made "canned" answer. For one thing, your description is
>too vague to effectively do that. Good luck.
> -=- Larry -=-
The concept I was asking about was a master list with my example of
1,2,3 as a index for the second and third items. It was suggested to
make my task easier. It turns out that it didn't.
Thanks for all the suggestions, though.
More information about the Python-list