I am out of trial and error again Lists

Seymore4Head Seymore4Head at Hotmail.invalid
Wed Oct 22 23:04:00 CEST 2014


On Wed, 22 Oct 2014 16:57:00 -0400, Joel Goldstick
<joel.goldstick at gmail.com> wrote:

>On Wed, Oct 22, 2014 at 4:30 PM, Seymore4Head
><Seymore4Head at hotmail.invalid> wrote:
>> def nametonumber(name):
>>     lst=[""]
>>     for x,y in enumerate (name):
>>         lst=lst.append(y)
>>     print (lst)
>>     return (lst)
>> a=["1-800-getcharter"]
>> print (nametonumber(a))#18004382427837
>>
>>
>> The syntax for when to use a () and when to use [] still throws me a
>> curve.
>() is tuples which are immutable which means that the items can't be
>changed.  [] is list which means that each item can be changed.
>Tuples are useful because they can be used as keys in dictionaries and
>are guarantied not to change.  Lists are useful because they can be
>updated.
>
>What you are doing confuses me.  You don't use x, which is the enumerated value.
>
>FIrst lst should be lst = [] .  You don't need to set the first
>element in the list to an empty string.  You just want to establish
>that you have an empty list called lst
>Second, you don't need lst = lst.append(y) because you can just say
>lst.append(y).  This will append the y value to the end of the list.
>As to converting letters to the corresponding numbers on a phone
>keypad, you don't show you code here for that
>>
>> For now, I am trying to end up with a list that has each character in
>> "a" as a single item.
>>
>> I get:
>> None
>> None
>> --
>> https://mail.python.org/mailman/listinfo/python-list

The lst=lst.append(y)
Was the mistake I never could see.

I am using enumerate just for practice.  To me that is just as easy as
typing len(something) and it seems more flexible.

and.......the reason I don't show the code for the conversions is that
I haven't got that far yet.  :)

Thank you



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