I am out of trial and error again Lists

Seymore4Head Seymore4Head at Hotmail.invalid
Fri Oct 24 20:20:37 CEST 2014

I meant to type:
if y in range(1,10) doesn't work.

On Fri, 24 Oct 2014 14:15:13 -0400, Seymore4Head
<Seymore4Head at Hotmail.invalid> wrote:

>On Fri, 24 Oct 2014 11:52:15 -0600, Ian Kelly <ian.g.kelly at gmail.com>
>>On Fri, Oct 24, 2014 at 11:03 AM, Seymore4Head
>><Seymore4Head at hotmail.invalid> wrote:
>>> Actually I was a little frustrated when I added that line back in as
>>> the other lines all work.
>>> Using list(range(10)) Doesn't throw an error but it doesn't work.
>>> http://i.imgur.com/DTc5zoL.jpg
>>> The interpreter.   I don't know how to use that either.
>>Try both of these in the interpreter, and observe the difference:
>>7 in range(10)
>>"7" in range(10)
>>Do you understand what the difference between 7 and "7" is?
>I do understand that.  7 is a number and "7" is a string.
>What my question was...and still is...is why
>Python 3 fails when I try using
>y=1 800 get charter
>y in range str(range(10))
>should work because y is a string and str(range(10)) should be
>"y" in str(1) fails.
>It doesn't give an error it's just not True when y is a number.
>These hints are just not working.  I am too thick for hints. :)
>If you could use it in the code, I might understand.
>The other work arounds that were posted work.
>I have used them.  str(range(10)) doesn't work.
>import string
>def nametonumber(name):
>    lst=[]
>    nx=[]
>    digit=[]
>    digit="".join(str(i) for i in range(10))
>    for x in name:
>        lst.append(x)
>    for y in (lst):
>        if y in list(range(1,10)):
>        #if y in "1234567890":
>        #if y.isdigit():
>        #if y in digit:       
>        #if y in string.digits:
>            nx.append(y)
>        if y in " -()":
>            nx.append(y)
>        if y in "abc":
>            nx.append("2")
>        if y in "def":
>            nx.append("3")
>        if y in "ghi":
>            nx.append("4")
>        if y in "jkl":
>            nx.append("5")
>        if y in "mno":
>            nx.append("6")
>        if y in "pqrs":
>            nx.append("7")
>        if y in "tuv":
>            nx.append("8")
>        if y in "wxyz":
>            nx.append("9")
>    number="".join(e for e in nx)
>    return number
>print (nametonumber(a))#1800 438 2427 837
>a="1-800-leo laporte"
>print (nametonumber(a))
>a="1 800 dialaho"
>print (nametonumber(a))

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