I am out of trial and error again Lists
Mark Lawrence
breamoreboy at yahoo.co.uk
Fri Oct 24 03:05:01 EDT 2014
On 22/10/2014 21:30, Seymore4Head wrote:
> def nametonumber(name):
> lst=[""]
> for x,y in enumerate (name):
> lst=lst.append(y)
> print (lst)
> return (lst)
> a=["1-800-getcharter"]
> print (nametonumber(a))#18004382427837
>
>
> The syntax for when to use a () and when to use [] still throws me a
> curve.
>
> For now, I am trying to end up with a list that has each character in
> "a" as a single item.
>
> I get:
> None
> None
>
Following on from the numerous responses you've had here, I've no idea
if this helps your thought processes but there's only one way for you to
find out http://www.greenteapress.com/thinkpython/ :)
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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