My backwards logic

MRAB python at
Fri Sep 5 18:57:56 CEST 2014

On 2014-09-05 17:48, Seymore4Head wrote:
> I'm still doing practice problems.  I haven't heard from the library
> on any of the books I have requested.
> This is not a hard problem, but it got me to thinking a little.  A
> prime number will divide by one and itself.  When setting up this
> loop, if I start at 2 instead of 1, that automatically excludes one of
> the factors.  Then, by default, Python goes "to" the chosen count and
> not "through" the count, so just the syntax causes Python to rule out
> the other factor (the number itself).
> So this works:
> while True:
>      a=random.randrange(1,8)
>      print (a)
>      for x in range(2,a):
>          if a%x==0:
>              print ("Number is not prime")
>              break
>      wait = input (" "*40  + "Wait")
> But, what this instructions want printed is "This is a prime number"
> So how to I use this code logic NOT print (not prime) and have the
> logic print "This number is prime"
Look for a factor. If you don't find one, it's a prime number.

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