My backwards logic

Bob Gailer bgailer at gmail.com
Fri Sep 5 19:04:30 CEST 2014


Bob gailer
On Sep 5, 2014 12:51 PM, "Seymore4Head" <Seymore4Head at hotmail.invalid>
wrote:
>
> I'm still doing practice problems.  I haven't heard from the library
> on any of the books I have requested.
>
>
http://www.practicepython.org/exercise/2014/04/16/11-check-primality-functions.html
>
> This is not a hard problem, but it got me to thinking a little.  A
> prime number will divide by one and itself.  When setting up this
> loop, if I start at 2 instead of 1, that automatically excludes one of
> the factors.  Then, by default, Python goes "to" the chosen count and
> not "through" the count, so just the syntax causes Python to rule out
> the other factor (the number itself).
>
> So this works:
> while True:
>     a=random.randrange(1,8)
>     print (a)
>     for x in range(2,a):
>         if a%x==0:
>             print ("Number is not prime")
>             break
       else:
           print ...
>     wait = input (" "*40  + "Wait")
>
> But, what this instructions want printed is "This is a prime number"
> So how to I use this code logic NOT print (not prime) and have the
> logic print "This number is prime"
>
> --
> https://mail.python.org/mailman/listinfo/python-list
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