__qualname__ in python 3.3
__peter__ at web.de
Sat Sep 6 18:47:44 CEST 2014
ISE Development wrote:
> When a class is defined within a function, the class generation function's
> '__qualname__' attrbute is not qualified a name.
> For instance:
> def test():
> class T:
> def method(self):
> t = T()
> When tracing a call to 'test()' using 'sys.settrace()', extracting the
> 'code' object from the frames of 'call' events and matching it to a
> 'function' object (using 'gc.get_referrers()') results in the following:
> 'code' object 'function' object
> ---------------- ------------------------------------
> co_name: test __qualname__: test
> co_name: T __qualname__: T
> co_name: method __qualname__: test.<locals>.T.method
> The second call corresponds to the class definition and not the call to
> the constructor (which is in fact a call to 'object.__init__', a C
> function hence not traced as a 'call' event - I checked this by
> disassembling the code object).
> I would expect the second call's '__qualname__' to be 'test.<locals>.T'.
> Can this be considered a bug? If so, I'll open one.
I don't understand what you are doing, so I tried to reproduce the
unqualified class name in 3.4 with the simpler approach of returning T:
Python 3.4.0 (default, Apr 11 2014, 13:05:11)
[GCC 4.8.2] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> def test():
... class T:
... def method(self): pass
... return T
>>> T = test()
If you do it that way with 3.3 (I don't have it handy) do you still see
T instead of test.<locals>.T?
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