Python 3 sort() problem
Mark Lawrence
breamoreboy at yahoo.co.uk
Mon Aug 17 10:18:45 EDT 2015
On 17/08/2015 12:42, Владислав wrote:
> # first: works fine
>
> x = [1, 2, 4, 2, 1, 3]
> x = list(set(x))
> x.sort()
> print(x) /# output: 1, 2, 3, 4
>
> /# second: why x became None ??
>
> x = [1, 2, 4, 2, 1, 3]
> x = list(set(x)).sort()
> print(x) /# output: None/
>
> I know that sort() returns None, but I guess that it would be returned x
> that was sorted. Why so?/
A set is created from x. This is converted to a list. You call sort()
and assign the return value from that, None, to x. You will see exactly
the same thing above if you do:-
x = x.sort()
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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