# Help with map python 2

Peter Otten __peter__ at web.de
Sun Jan 4 17:33:14 CET 2015

```flebber wrote:

> In repsonse to this question: Write a program that prints the first 100
> members of the sequence 2, -3, 4, -5, 6, -7, 8.
>
> This is my solution it works but ugly.
>
> series = range(2,100)
> # answer = [(x,(y* -1)) for x, y in series[::2]]
> for item in series:
>     if item % 2 != 0:
>     else:
>

Hm, that's the only first 98 members.

>
> I know I should be better off doing this with map but cannot get it to
> work. I understand also that map returns a generator so this solution
> should only working in python2(correct me please if I am wrong).
>
> In [6]: map?
> Type:       builtin_function_or_method
> String Form:<built-in function map>
> Namespace:  Python builtin
> Docstring:
> map(function, sequence[, sequence, ...]) -> list
>
> Just getting something wrong
> list(map((lambda x: x * -1 if (x%2 != 0)), series))

Here's another way to look at the problem -- start with an infinite series
and then slice it:

>>> from itertools import *
>>> list(islice(count(2), 10))
[2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

Factor out the slicing to focus on the important stuff:

>>> def first_ten(items):
...     return list(islice(items, 10))
...
>>> first_ten(count(2))

>>> first_ten(cycle([1, -1]))
[1, -1, 1, -1, 1, -1, 1, -1, 1, -1]

Combine the two:

>>> from operator import mul
>>> first_ten(imap(mul, cycle([1, -1]), count(2)))
[2, -3, 4, -5, 6, -7, 8, -9, 10, -11]

It is important that you use itertools.imap() in Python 2 because the map()
builtin would try to build the infinite list...

Finally put the slicing back into the expression if you like:

>>> list(islice(imap(mul, cycle([1, -1]), count(2)), 10))
[2, -3, 4, -5, 6, -7, 8, -9, 10, -11]

```