where in Nan defined
ian.g.kelly at gmail.com
Fri Jan 9 03:12:45 CET 2015
On Thu, Jan 8, 2015 at 7:07 PM, Chris Angelico <rosuav at gmail.com> wrote:
> On Fri, Jan 9, 2015 at 12:46 PM, Steven D'Aprano
>> The fallback rule I use when float('nan') fails is
>> INF = 1e3000 # Hopefully, this should overflow to INF.
>> NAN = INF-INF # And this hopefully will give a NaN.
> The first question is "will 1eN overflow to inf?". I'm fairly sure
> Python guarantees that an unrepresentable float constant will be
> treated as infinity, so all you have to do is crank up the exponent
> any time you suspect it'll be representable.
Or to never have to worry about it:
INF = 1e400
while not math.isinf(INF):
INF *= INF
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