Testing random
sohcahtoa82 at gmail.com
sohcahtoa82 at gmail.com
Fri Jun 12 18:55:08 EDT 2015
On Friday, June 12, 2015 at 3:12:26 PM UTC-7, Thomas 'PointedEars' Lahn wrote:
> Ian Kelly wrote:
>
> > [...] Thomas 'PointedEars' Lahn [...] wrote:
> >> Ian Kelly wrote:
> >>> The probability of 123456789 and 111111111 are equal. The probability
> >>> of a sequence containing all nine numbers and a sequence containing
> >>> only 1s are *not* equal.d
> >> There is a contradiction in that statement. Can you find it?
> >
> > Yes. I phrased my statement as if I were addressing a rational
> > individual, in clear contradiction of the current evidence.
> >
> > Seriously, if you reject even the statement I made above, in spite of
> > all the arguments that have been advanced in this thread, in spite of
> > the fact that this is very easy to demonstrate empirically, then I
> > don't think there's any fertile ground for discussion here.
>
> /Ad hominem/ when out of arguments. How typical.
>
> Do you deny that "123456789" *is* "a sequence containing all nine numbers"
> (digits, really), and that "111111111" *is* "a sequence containing only 1s"?
>
> Do you deny that therefore your second sentence contradicts the first one?
>
> --
> PointedEars
>
> Twitter: @PointedEars2
> Please do not cc me. / Bitte keine Kopien per E-Mail.
I'm struggling to see the contradiction here.
Yes, 123456789 is a sequence containing all nine numbers. And as someone else said, 123456798 is also a sequence containing all numbers. 987654321 contains all numbers. There are 9*8*7*6*5*4*3*2*1 (Usually expressed as "9!", and equal to 362,880) distinct ways to order nine numbers.
However, there is only ONE way to order a series of all 1s.
There's no contradiction here.
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