a *= b not equivalent to a = a*b

[Christian Gollwitzer]

Am 26.08.16 um 09:53 schrieb Erik:
> On 26/08/16 08:44, mlzarathustra at gmail.com wrote:
>> Here's the key:
>>
>> $ python2
>> Python 2.7.10 ...
>>>>> 1/2
>> 0
>>>>>
>>
>> $ python
>> Python 3.5.1 ...
>>>>> 1/2
>> 0.5
>>>>> 1//2
>> 0
>>>>>
>>
>> I read about this awhile ago, but it's not until it bites you that you
>> remember fully.
>
> How is this related to your question? The example explicitly says Python
> 2 and doesn't use the '//' operator.
>

It's related by the fact that a*b/c performs integer division (intended 
by the OP) which gives a different result than a*(b/c) (unintended by 
the OP). Floating point (as in Python 3) *also* may give a different 
result, but the deviation from the "true", i.e. mathematical value, is 
far less than with integer arithmetics.

	Christian