General computer language, syntax question.
joel.goldstick at gmail.com
Mon Feb 29 08:55:19 EST 2016
On Mon, Feb 29, 2016 at 8:45 AM, <jonas.thornvall at gmail.com> wrote:
> I have a problem programming uniform networks, "x nodes with y links" that
> turn out to be really hairy to solve for me and i feel i really lack the
> programming features
> programming languages including Pyhton.
> For a beautiful solution it would require "If in list/array return
> boolean" "If not in list/array return boolean".
> boolean value "inlist" to false and loop thru, to see if it is already in
> list. If not it is added to list.
> So if the current node i generate links for is x and i try to generate a
> link to node z, and z's links exhausted i will add it to exhausted list.
> And if there is node-x exhausted entries in list, well then script should
> break because it will lock into a cycle. The cyclic lockup is due to only a
> subset of the networks on the form (links*deep)+1=nodes is possible.
> So what i need is to know howto write "if list/array ***empty*** do
> I sure know howto check if an array have 1 element 2,3,4 but how do you
> check for empty.
> I think it is crazy that you can not do general comparissons of the type
> If in list/array
> If not in list/array
> But it is even more crazy that you can not check if list/array is empty,
> that is just madness.
>>> l = [1,2,3,4]
>>> if 1 in l:
... print 1
>>> if 6 in l:
... print 1
>>> l = 
>>> if len(l) == 0:
... print 'empty'
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