list index out of range Error , need to fix it or ignore it
Joel Goldstick
joel.goldstick at gmail.com
Sat Feb 27 12:21:10 EST 2016
On Sat, Feb 27, 2016 at 12:01 PM, Ganesh Pal <ganesh1pal at gmail.com> wrote:
> changed baddr="" to file ="" in the example program , sorry for the typo
>
> > filename='/tmp2/2.txt'
> >
> > def check_file():
>
don't use global filename. just pass filename into check_file
def check_file(filename):
> > """
> > Run the command parallel on all the machines , if there is a
> > file named /tmp/file2.txt extract file2.txt
> >
> > """
> > global filename
> > file = ''
> > cmd = ("run_al_paral 'ls -al %s'" % (filename))
> > print(cmd)
> > stdout, stderr, exitcode = run(cmd)
>
what is run(...)
> > print(stdout)
> > lines = stdout.strip().split('\n')
> > print(lines)
> > for line in lines:
> > if 'exited' in lines:
> > continue
> >
> > file = lines[0].split()[9][6:]
> > break
> > print file
> > return file
> >
> > def main():
> > functions = [check_file]
> > for func in functions:
> > try:
> > func()
> > except Exception as e:
>
not a good idea to have catchall exception
> > return False
> > if __name__ == '__main__':
> > main()
> >
> --
>
copy and paste your traceback
> https://mail.python.org/mailman/listinfo/python-list
>
--
Joel Goldstick
http://joelgoldstick.com/ <http://joelgoldstick.com/stats/birthdays>
http://cc-baseballstats.info/
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