Is '*args' useful in this example code?
Antoon Pardon
antoon.pardon at rece.vub.ac.be
Tue Jan 5 06:51:52 EST 2016
Op 05-01-16 om 03:16 schreef Robert:
> Hi,
>
> I find an example code on wrap at this link:
> http://stackoverflow.com/questions/308999/what-does-functools-wraps-do
>
> Here is the code:
> ////////
> def logged(func):
> def with_logging(*args, **kwargs):
> print func.__name__ + " was called"
> return func(*args, **kwargs)
> return with_logging
> ///////
>
> I understand now, but I feel the args usage is weird. I don't see any way
> to use *args and **kwargs in above code. What is your opinion on it?
>
>
> Thanks,
You want the following to work
def add(a, b):
return a + b
def double(n)
return n + n
logged_add = logged(add)
logged_double = logged(double)
s = logged_add(3, 5)
d = logged_double(13)
--
Antoon Pardon
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