Best way to clean up list items?

[justin walters]

On May 2, 2016 10:03 AM, "Jussi Piitulainen" <jussi.piitulainen at helsinki.fi>
wrote:
>
> DFS writes:
>
> > Have: list1 = ['\r\n   Item 1  ','  Item 2  ','\r\n  ']
> > Want: list1 = ['Item 1','Item 2']
> >
> >
> > I wrote this, which works fine, but maybe it can be tidier?
> >
> > 1. list2 = [t.replace("\r\n", "") for t in list1]   #remove \r\n
> > 2. list3 = [t.strip(' ') for t in list2]            #trim whitespace
> > 3. list1  = filter(None, list3)                     #remove empty items
> >
> > After each step:
> >
> > 1. list2 = ['   Item 1  ','  Item 2  ','  ']   #remove \r\n
> > 2. list3 = ['Item 1','Item 2','']              #trim whitespace
> > 3. list1 = ['Item 1','Item 2']                 #remove empty items

You could also try compiled regex to remove unwanted characters.

Then loop through the list and do a replace for each item.