why this code loop forever after a draw a rectangle
Gary Herron
gherron at digipen.edu
Fri Sep 16 15:14:30 EDT 2016
On 09/16/2016 04:24 AM, meInvent bbird wrote:
> im = img.copy()
> cntcounter = 0
> for cnt in contours:
> epsilon = 0.1*cv2.arcLength(cnt,True)
> approx = cv2.approxPolyDP(cnt,epsilon,True)
> #peri = cv2.arcLength(cnt, True)
> #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
> #print("len(approx)="+str(len(approx)))
> if len(approx) == 4:
> print("approx=" + str(approx))
> cntcounter = cntcounter + 1
> print("here1")
> x,y,w,h = cv2.boundingRect(cnt)
> print("here2")
> while im is None:
> time.sleep(1)
> if im is not None:
> print("here3")
> im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
> #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
> #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
> #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
> #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)
>
>
> cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)
These two lines:
while im is None:
time.sleep(1)
are an infinite loop if im is None;
Since you haven't told us what im (or img, contours, cv2) are, I can't
tell how im might become None, but it does look like you (confusingly)
use im for two different things: an img.copy() and a cv2.rectangle,
whatever those may be.
Pure guesswork: if cv2.rectangle draws a rectangle, what does it
return? If it doesn't return anything, the line
im = cv2.rectangle(...)
is how im gets the value of None.
--
Dr. Gary Herron
Professor of Computer Science
DigiPen Institute of Technology
(425) 895-4418
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