Challenge: find the first value where two functions differ
Steve D'Aprano
steve+python at pearwood.info
Fri Aug 4 13:51:11 EDT 2017
On Sat, 5 Aug 2017 02:31 am, MRAB wrote:
> Why would isqrt_float not give the correct answer? Probably because of
> truncation (or rounding up?) of the floating point. I'd expect it to
> fail first near a square.
Assuming your math.sqrt() is an IEEE-754 correctly-rounded square root, and that
int() correctly truncates, the only source of errors is that not all integers
are representable as floats.
No integer larger than or equal to 2**1024 can be represented as a float.
No *odd* integer larger than 2**53 can be represented as a float.
Between 2**53 and 2**54, float can only represent multiples of 2.
Between 2**54 and 2**55, float can only represent multiples of 4.
Between 2**55 and 2**56, float can only represent multiples of 8.
And so on.
--
Steve
“Cheer up,” they said, “things could be worse.” So I cheered up, and sure
enough, things got worse.
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