Problem With Tkinter Font

[Wildman]

On Sun, 26 Feb 2017 09:17:00 +0100, Peter Otten wrote:

> Wildman via Python-list wrote:
> 
>> Python 3.4.2
>> Tkinter 8.6
>> Linux
>> 
>> I want to set the font in a GUI program I am working on.
>> Here is the pertinent code I am using...
>> 
>> from tkinter import font
>> 
>> myfont = font.Font(family='Helvetica', size=10, weight='bold')
>> 
>> Here is the error I get...
>> 
>> Traceback (most recent call last):
>>   File "./test.py", line 41, in <module>
>>     myfont = font.Font(family='Helvetica', size=10, weight="bold")
>>   File "/usr/lib/python3.4/tkinter/font.py", line 93, in __init__
>>     tk.call("font", "create", self.name, *font)
>> AttributeError: 'NoneType' object has no attribute 'call'
>> 
>> From my research, the syntax is correct but I am having
>> doubts.  Can anyone clarify?
> 
> If you do not provide the root argument there is still an implicit 
> dependency:
> 
> """
> class Font:
> ...
>     def __init__(self, root=None, font=None, name=None, exists=False,
>                  **options):
>         if not root:
>             root = tkinter._default_root
>         tk = getattr(root, 'tk', root)
> 
> """
> 
>>>> import tkinter
>>>> from tkinter import font
>>>> font.Font(family="Helpvetica", size=10, weight="bold")
> Traceback (most recent call last):
>   File "<stdin>", line 1, in <module>
>   File "/usr/lib/python3.4/tkinter/font.py", line 93, in __init__
>     tk.call("font", "create", self.name, *font)
> AttributeError: 'NoneType' object has no attribute 'call'
>>>> root = tkinter.Tk()
>>>> font.Font(family="Helpvetica", size=10, weight="bold")
> <tkinter.font.Font object at 0x7fb9fdfdb6d8>
> 
> So you have to create the main window before you can create a Font.

OK, that makes sense.  I knew I was doing something dumb
or in this case, not doing it.  Thank you.

-- 
<Wildman> GNU/Linux user #557453
The cow died so I don't need your bull!