# list of the lists - append after search

Andrew Zyman formisc at gmail.com
Thu Mar 2 15:53:16 EST 2017

```On Thursday, March 2, 2017 at 3:31:36 PM UTC-5, Jussi Piitulainen wrote:
> Andrew Zyman writes:
>
> > On Thursday, March 2, 2017 at 2:57:02 PM UTC-5, Jussi Piitulainen wrote:
> >> Peter Otten <__peter__ at web.de> writes:
> >>
> >> > Andrew Zyman wrote:
> >> >
> >> >> On Thursday, March 2, 2017 at 11:27:34 AM UTC-5, Peter Otten wrote:
> >> >>> Andrew Zyman wrote:
> >> >>> .....
> >> >>> .....
> >> >>> > End result:
> >> >>> >  ll =[ [a,1], [b,2], [c,3], [blah, 1000, 'new value'] ]
> >> >>>
> >> >>> >>> outer = [["a", 1], ["b", 2], ["c", 3], ["blah", 1000]]
> >> >>> >>> for inner in outer:
> >> >>> ...     if inner[0] == "blah":
> >> >>> ...         inner.append("new value")
> >> >>
> >> >> thank you. this will do.
> >> >> Just curious, is the above loop can be done in a one-liner?
> >> >
> >> > Ah, that newbie obsession ;)
> >> >
> >> >>>> outer = [["a", 1], ["b", 2], ["c", 3], ["blah", 1000]]
> >> >>>> [inner + ["new value"] if inner[0] == "blah" else inner for inner in
> >> > outer]
> >> > [['a', 1], ['b', 2], ['c', 3], ['blah', 1000, 'new value']]
> >> >
> >> > Note that there is a technical difference to be aware of -- matching
> >> > lists are replaced rather than modified.
> >>
> >> I take it you are too sane, or too kind, to suggest the obvious
> >> solution:
> >>
> >> >>> outer = [["a", 1], ["b", 2], ["c", 3], ["blah", 1000]]
> >> >>> [inner.append("new value") for inner in outer if inner[0] == "blah"]
> >> [None]
> >> >>> outer
> >> [['a', 1], ['b', 2], ['c', 3], ['blah', 1000, 'new value']]
> >>
> >> [snip]
> >
> > Arh!!! this is it :)
> >
> > I'm sure i'll regret this line of code in 2 weeks - after i
> > successfully forget what i wanted to achieve :)
>
> Jokes aside, you should strive to express your intention in your code.
> Be kind to your future self. Write the three-line loop if you want
> in-place modification.
>
> I use comprehensions a lot, but not to save lines. I might make Peter's
> expression above a four-liner to make its structure more visible:
>
>   res = [ ( inner + ["new value"]
>             if inner[0] == "blah"
>             else inner )
>           for inner in outer ]
>
> Maybe.

thank you gentlemen. This is very helpful discussion and i appreciate your explanations - helped a lot.
```