Passing yield as a function argument...
Christopher Reimer
christopher_reimer at icloud.com
Tue May 23 22:59:18 EDT 2017
Greetings,
I have two functions that I generalized to be nearly identical except
for one line. One function has a yield statement, the other function
appends to a queue.
If I rewrite the one line to be a function passed in as an argument --
i.e., func(data) -- queue.append works fine. If I create and pass an
inner function with the yield statement, nothing happens.
Is it possible to pass a yield statement in some form as a function
argument?
Thank you,
Chris Reimer
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