Python 2 -> 3, urllib.urlOpen
Mark Lawrence
breamoreboy at yahoo.co.uk
Sat Oct 14 15:25:06 EDT 2017
On 13/10/17 23:27, Irv Kalb wrote:
> One of the colleges where I teach has just moved from Python 2 to Python 3. I am in the process of converting my beginning Python class from Python 2 to Python 3. Everything has gone smoothly, until I just tried to convert some code that imports and uses urllib.urlOpen to fetch data through an API. I am using an API that I found here: http://www.jarloo.com/yahoo_finance/ <http://www.jarloo.com/yahoo_finance/>
>
> As a minimal example, I am trying to get the latest stock price for Apple.
>
> The following example works perfectly in Python 2:
>
> import urllib
>
> # set the Yahoo finance url, set stock name, ask for last price
> fullURLWithParameters = 'http://finance.yahoo.com/d/quotes.csv?s=aapl&f=l1'
>
> # read all the data
> response = urllib.urlopen(fullURLWithParameters).read()
>
> print 'Response is: ', response
>
> This is asking for a stock name (s=) and I am adding in aapl as a stock symbol. I am also adding a "flag" parameter (f=) and setting it to l1 to get the last trade price. When I run this in Python 2, I see:
>
> Response is: 156.99
>
>
> If I take the same program and just modify the print statement to add parentheses, then try to run it in Python 3.6 (on a Mac):
>
>
> import urllib
>
> # set the Yahoo finance url, set stock name, ask for last price
> fullURLWithParameters = 'http://finance.yahoo.com/d/quotes.csv?s=aapl&f=l1'
>
> # read all the data
> response = urllib.urlopen(fullURLWithParameters).read()
>
> print('Response is: ', response)
>
> I get the following:
>
> Traceback (most recent call last):
> File " .... s/StockQuoteYahooAPIMinimal.py", line 9, in <module>
> response = urllib.urlopen(fullURLWithParameters).read()
> AttributeError: module 'urllib' has no attribute 'urlopen'
>
>
> I've looked at the Python 3.6 documentation for urllib, and I see that certain calls have been changed and others have been eliminated. But my eyes glaze over trying to figure out what to use instead.
>
> My question is: Is there a simple (hopefully one or two line) replacement for my call to url lib.urlopen(<URL>).read()
>
> I know that there are other modules out there that handle requests (like the Requests module), but this is a strictly controlled university environment. I cannot download any external packages (other then pygame, which I got special permission for) onto the computers in the school. Therefore, I'm looking for something in the Python 3.6 Standard Library.
>
> Thanks in advance,
>
> Irv
>
Hopefully this https://docs.python.org/3/howto/pyporting.html will help.
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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