For Loop Dilema [python-list]
Ian Kelly
ian.g.kelly at gmail.com
Mon Feb 26 10:20:33 EST 2018
On Sun, Feb 25, 2018 at 8:05 PM, INADA Naoki <songofacandy at gmail.com> wrote:
> https://docs.python.org/3.6/library/itertools.html#itertools.product
I don't see how you would use itertools.product to do what the OP
asked for. You could use itertools.chain.from_iterable, though:
py> names = ['Jack', 'Susan']
py> list(chain.from_iterable(names))
['J', 'a', 'c', 'k', 'S', 'u', 's', 'a', 'n']
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