Quick survey: locals in comprehensions (Python 3 only)
Antoon Pardon
antoon.pardon at vub.be
Tue Jun 26 06:04:16 EDT 2018
On 26-06-18 11:22, Steven D'Aprano wrote:
> On Tue, 26 Jun 2018 10:20:38 +0200, Antoon Pardon wrote:
>
>>> def test():
>>> a = 1
>>> b = 2
>>> result = [value for key, value in locals().items()]
>>> return result
> [...]
>
>> I would expect an UnboundLocalError: local variable 'result' referenced
>> before assignment.
> Well, I did say that there's no right or wrong answers, but that
> surprises me. Which line do you expect to fail, and why do you think
> "result" is unbound?
I would expect the third statement to fail because IMO we call the locals
function before result is bound. But result is a local variable so the
locals function will try to reference it, hence the UnboundLocalError.
--
Antoon Pardon.
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