Regex Doubts

[Iranna Mathapati]

Thanks a lot Antoon.



On Fri, Mar 30, 2018 at 2:51 PM, Antoon Pardon <antoon.pardon at vub.be> wrote:

> On 30-03-18 08:16, Iranna Mathapati wrote:
> > Hi Team,
> >
> >
> > how to achieve fallowing expected output?
> >
> > str_output= """
> >
> > MOD1 memory                              : 2 valid    1790 free
> > MOD2 memory                              : 128 valid   128 free
> > UDP Aware *MEMR*                            : 0 valid   0 free *MEMR
> >                                    : 21 valid   491 free
> > <<<<<expecting *
> > Feature XYZ                              : 3 valid    13 free
> > Feature PQR                       : 0 valid 16 free
> > Feature MNO                        : 0 valid 2 free
> >
> >  """
> >
> > i am going to grep MEM values alone and i have tried fallowing Regex:
> >
> > re.findall(r'MEMR\s+\:\s+([0-9]+)\s+valid \s+([0-9]+)\s+free ',
> str_output)
> >
> > it produce fallowing output::
> > [('0', '0'), ('21', '491')]
> >
> > Expected output and i am expecting fallowing output::
> > *[('21' ,'491')]  <<<<< how to achieve this output?*
>
> I find it hard to find a good answer to your question because you give no
> reason why you want to reject the ('0', '0') result.
>
> Are you uninterested in 0 results?
> Are you only interested in lines that start with MEMR and so are not
> interested
> in lines where the MEMR comes later?
>
> In the first case you can write:
> print(re.findall(r'MEMR\s+\:\s+([1-9][0-9]*)\s+valid
> \s+([1-9][0-9]*)\s+free', str_output))
>
> In the second case you can write:
> regex = re.compile(r'^MEMR\s+\:\s+([0-9]+)\s+valid \s+([0-9]+)\s+free',
> re.MULTILINE)
> print(regex.findall(str_output))
>
>
>
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>