How to fill in a dictionary with key and value from a string?
MRAB
python at mrabarnett.plus.com
Fri Mar 30 16:37:15 EDT 2018
On 2018-03-30 21:13, C W wrote:
> Hello all,
>
> I want to create a dictionary.
>
> The keys are 26 lowercase letters. The values are 26 uppercase letters.
>
> The output should look like:
> {'a': 'A', 'b': 'B',...,'z':'Z' }
>
> I know I can use string.ascii_lowercase and string.ascii_uppercase, but how
> do I use it exactly?
> I have tried the following to create the keys:
>
> myDict = {}
> for e in string.ascii_lowercase:
> myDict[e]=0
>
> But, how to fill in the values? Can I do myDict[0]='A', myDict[1]='B', and
> so on?
>
The uppercase equivalent of what's in "e" is "e.upper()". Does that help?
Alternatively, string.ascii_lowercase will give you the keys and
string.ascii_uppercase will give you the values for a dict; use "zip" to
make them into pairs (2-tuples) and then pass the list/generator into
"dict":
dict(zip(string.ascii_lowercase, string.ascii_uppercase))
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