why do I get syntax error on if <code>: break
Steven D'Aprano
steve+comp.lang.python at pearwood.info
Thu May 24 22:27:25 EDT 2018
On Thu, 24 May 2018 19:12:33 -0700, asa32sd23 wrote:
> here is the code, i keep getting an error, "break outside loop". if it
> is false just exit function
break doesn't exit the function, it exits the loop. There is no loop to
exit, so it is an error.
Believe the compiler when it tells you there is a syntax error with your
code. The compiler is always correct.
--
Steve
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