Error Python version 3.6 does not support this syntax.
Terry Reedy
tjreedy at udel.edu
Tue Nov 27 11:55:24 EST 2018
On 11/27/2018 7:50 AM, srinivasan wrote:
> Dear Python Experts,
>
> As still I am newbie and learning python, I am trying to reuse the
> Bluetoothctl wrapper in Python from the link (
> https://gist.github.com/egorf/66d88056a9d703928f93
Created in 2015
> ) I am using python3.6
> version, In pycharm editor on the bold highlighted code snippets I see the
> error message "Python version 3.6 does not support this syntax.",
No version of Python 3 supports the the old exception statement syntax.
Python 2.7, released in 2010, supports both the old and the new syntax.
I am not sure about 2.6 and before. It is odd to me that someone would
use both the new print syntax and old except syntax together in 2015.
> Could you please how help me how the below highlighted lines of code can be
> can be ported to python3.6 version?
>
> * except BluetoothctlError, e:*
If you run the code through the lib2to3 converter it will change ', ' to
' as '. I have not
> Full Code snippet:
Not needed, however start_scan and make_discoverable are a bit flakey.
As written, out is discarded making the assignment to out useless and
the 'return None' redundant (since the function always returns None). I
suspect that this is a bug.
> def start_scan(self):
> """Start bluetooth scanning process."""
> try:
> out = self.get_output("scan on")
> except BluetoothctlError, e:
print(e) return None
--
Terry Jan Reedy
More information about the Python-list
mailing list