Explicit vararg values
Michael Torrie
torriem at gmail.com
Sun Sep 23 00:16:13 EDT 2018
On 09/16/2018 04:39 PM, Buck Evan wrote:
> The syntax I'm proposing is:
> f(**kwargs={'a': 1, 'b': 2})
>
> as a synonym of f(a=1, b=2) when an appropriate dictionary is already on
> hand.
But if the kwargs dict already exists you can already unpack it:
f(**kwargs)
or
f(**{'a': 1, 'b': 2})
So I guess I'm unsure of how your proposal differs from this existing
syntax in use.
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